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GREYUIT [131]
3 years ago
8

Animals and people that take in more energy than they expend will get fatter. Here are data on 12 rhesus monkeys: 6 lean monkeys

(4% to 9% body fat) and 6 obese monkeys (13% to 14% body fat). The data report the energy expended in 24 hours (kilojoules per minute) and the lean body mass (kilograms, leaving out fat) for each monkey.
Lean Obese
Body Mass Energy Body Mass Energy
6 1.13 8 0.96
7.5 1.07 9.1 1.43
9.2 1.47 10.3 1.11
9.7 1.68 12 1.4
9.1 1.08 11.9 1.27
9.1 1.18 11.2 1.37
(a) What is the mean lean body mass of the lean monkeys?
(b) What is the mean lean body mass of the obese monkeys?
Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

mean lean body mass of the lean monkeys = 8.4kg

mean lean body mass of the obese monkeys = 10.4kg

Step-by-step explanation:

a) Mean = Sum of Body mass/number of body mass

For lean monkeys, mean = (6+7.5+9.2+9.7+9.1+9.1)/6

Mean = 50.6/6

Mean = 8.4

b)

for obese monkeys, mean = (8+9.1+10.3+12+11.9+11.2)/6

Mean = 62.5/6

Mean = 10.4

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Step-by-step explanation:

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About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

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Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

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In conclusion, about $3692.47 should be deposited.

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