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GREYUIT [131]
3 years ago
8

Animals and people that take in more energy than they expend will get fatter. Here are data on 12 rhesus monkeys: 6 lean monkeys

(4% to 9% body fat) and 6 obese monkeys (13% to 14% body fat). The data report the energy expended in 24 hours (kilojoules per minute) and the lean body mass (kilograms, leaving out fat) for each monkey.
Lean Obese
Body Mass Energy Body Mass Energy
6 1.13 8 0.96
7.5 1.07 9.1 1.43
9.2 1.47 10.3 1.11
9.7 1.68 12 1.4
9.1 1.08 11.9 1.27
9.1 1.18 11.2 1.37
(a) What is the mean lean body mass of the lean monkeys?
(b) What is the mean lean body mass of the obese monkeys?
Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

mean lean body mass of the lean monkeys = 8.4kg

mean lean body mass of the obese monkeys = 10.4kg

Step-by-step explanation:

a) Mean = Sum of Body mass/number of body mass

For lean monkeys, mean = (6+7.5+9.2+9.7+9.1+9.1)/6

Mean = 50.6/6

Mean = 8.4

b)

for obese monkeys, mean = (8+9.1+10.3+12+11.9+11.2)/6

Mean = 62.5/6

Mean = 10.4

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During a period of 112 minutes, a music station played 40 minutes of commercials. What
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Answer:

9:5

Step-by-step explanation:

  1. 112 - 40 = 72. 112 represents the total time, but you are comparing music to commercials, so you have to subtract the commercial time from the total time.
  2. Find the GCF of 72 and 40, which is 8.
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2 years ago
The mayor of a town has proposed a plan for the annexation of a new bridge. A political study took a sample of 1000 voters in th
garri49 [273]

Answer:

z=\frac{0.42 -0.39}{\sqrt{\frac{0.39(1-0.39)}{1000}}}=1.945  

p_v =P(Z>1.945)=0.0259  

If we compare the p value obtained with the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.  

Step-by-step explanation:

1) Data given and notation  

n=1000 represent the random sample taken

\hat p=0.42 estimated proportion of residents who favored annexation

p_o=0.39 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.39:  

Null hypothesis:p\leq 0.39  

Alternative hypothesis:p > 0.39  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.42 -0.39}{\sqrt{\frac{0.39(1-0.39)}{1000}}}=1.945  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.945)=0.0259  

If we compare the p value obtained with the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 2% of significance the proportion of residents who favored annexation is not significantly higher than 0.39.  

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3,6,9,12,15
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The multiple that is common and is the lowest in both would be 15.

The solution thus is B.15, it is the LCD for the fractions of 2/3 and 4/5.
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