A disorder, which influences the skin, bones, and many hormone-generating tissues are known as a McCune-Albright syndrome. The individuals with the condition develop regions of unusual scar-like tissue in their bones, a state known as polyostotic fibrous dysplasia.
In the given case, the CPT and ICD-10-CM codes to be reported are 61564, Q78.1.
The frontal bone is the component of the cranium, in the CPT index when one looks for Excision/Cranial bone/Tumor, then one is directed to code range 61563-61564. As decompression of the optic nerve was also done, therefore, 61564 is the accurate code.
When one looks of McCune-Albright syndrome in the ICD-10-CM index, then one is directed towards Q78.1.
Answer:
By preventing the binding of ADP and Inoganic phosphate to the catalytic part ot ATP synthase.
Explanation:
The ATP synthase its a enzyme complex located at the membrane of mitochondria , that transforms ADP to ATP. To perform this reaction the ATP synthase, needs a gradient of H+. This gradient of H+ is made during electron transport chain. Once the gradient of H+ its made, the H+ passes through the ATP synthase and performs a conformational change to the enzymatic complex. This conformational change enables the catalytic part of the ATP synthase to be exposed, so that it can bind ADP and inorganic phosphate. After this substrates bind, a chemical reaction is performed between ADP and inorganic phosphate. The products of this reaction are ATP and water. Since Fat Away makes mitochondrial membrane permeable to H+, no gradient of H+ is established, and H+ can not pass through the ATP synthase. So no conformational change is made to the ATP synthase, and the catalytic part of the ezyme cant bind ADP and inorganic phosphate, to perform the synthesis of ATP.
It is anatomic dead space
The answer is: two cells
Explanation:-
At the last stage of mitotic division (telophase) the cell will divide into two cells