What is the range of 38 17 55 40

Mathematics

2 answers:

KengaRu [80]3 years ago

8 0

Answer:

55 - 17 = 38

Step-by-step explanation:

shtirl [24]3 years ago

7 0

Answer:

Step-by-step explanation:

take the biggest number and subtract it by the smallest number and you will get your answer.

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Which of the following is the same as cos15°

Vesna [10]

Answer:

cos15 is equivalent to sin(75)

Step-by-step explanation:

solving for cos15 degrees gives you ((√(3)+1)*√(2))/4 which is the same as the sin(75)

6 0

2 years ago

Melanie is looking for a loan. She is willing to pay no more than an effective rate of 9. 955% annually. Which, if any, of the f

Jlenok [28]

Melanie should take A and B, being r(loan a)= 9.699% annually, r(loan b)=9.862% annual

<h3>What options Melanie should choose for the best deal?</h3>

It is given that

Loan A: 9.265% nominal rate, compounded weekly

In order to find the easiest effective rate, we need to divide this rate by 52 (which are the weeks in a year). Once we do that, we convert this effective weekly rate into an effective annual rate. Let´s walk you through all this.

$r(Eweek)=\dfrac{0.09265}{52} =0.00178173$

Or 0.178173% effective weekly. Now we can transform it into an effective annual rate.

$r(e,a)=1+(r(e.week))^{52} -1$

$r(e,a)=1+(0.00178173)^{52} -1=0.09699$

Or 9.669% annual, which is less than 9.955%, so this one is selected, let´s check the next.

Loan B: 9.442% nominal rate, compounded monthly

Just like we did with Loan A, we need to divide this rate too, only this time, we will divide by 12, therefore obtaining an effective monthly rate.

$r(Emonth)=\dfrac{0.09442}{12} =0.00786833$

Or 0.786833% effective monthly, let´s turn it into an effective annual rate.

$r(e,a)=1+(r(e.month))^{12} -1$

$r(e,a)=1+(0.00786833))^{12} -1=0.09862$

Or 9.862% annual, so this rate would work for Melanie too. This means that option C) is the answer we are looking for but, let´s walk that extra mile and turn that Loan C rate into an annual rate.

$r(Eweek)=\dfrac{0.09719}{4} =0.0242975$