Question

Please answer even if there is already 1, last time i asked this i put a lot of points and a bot took them and i dont have time to wait for a second answer. im giving half points this time, 50, and i will give brainliest. dont be a cheapskate fishing for points either, dont answer if ur not gonna try. im sick of people doing that i just need help. its much appreciated if you can.
every year in delaware there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. the equation y = 15 + 110x - 16x^2 can be used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the pumpkin has been in the air. what is the maximum height that the pumpkin reaches? how many seconds have passed when the pumpkin hits the ground? (hint: if the pumpkin hits the ground, its height is 0 feet)

a. the pumpkins maximum height is 204.06 feet and it hits the ground after 7.01 seconds.

b. the pumpkins maximum height is 3.44 feet and it hits the ground after 7.01 seconds.

c. the pumpkins maximum height is 204.06 feet and it hits the ground after 3.44 seconds

d. the pumpkins maximum height is 3.44 feet and it hits the ground after 204.05 seconds.

Answer 1

Answer:

The answer would be A

Step-by-step explanation:

a. the pumpkins maximum height is 204.06 feet and it hits the ground after 7.01 seconds.