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mash [69]
3 years ago
14

863.141 in expanded form

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0
800
+ 60
+ 3
+ 0.1
+ 0.04
+ 0.001
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Write an equation for line N
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y=x-1

Step-by-step explanation:

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Move the slider on the graph on the right to graph each function:
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Answer:

The domain is x\geq 7

The range is y\geq 1

Step-by-step explanation:

we have

y=\sqrt{x-7} +1

<em>Find the domain</em>

Remember that

The domain of a function is the set of all possible values of x

we know that the radicand of the function must be greater than or equal to zero

so

x-7\geq 0

solve for x

x\geq 7

therefore

The domain is x\geq 7

<em>Find the range</em>

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

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therefore

The range is y\geq 1

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2 years ago
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Due today. Pls help.
alexandr1967 [171]
X is 19
Explanation: because the opposite side of the angle is 134 degrees the other side also has to be 134 degrees. So we do 134-20 which is 114 and then 114 divided by 6 because the number next to x is 6 and the number that is x has to be 19 as 19x6 is 114.
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i uploaded a vid on this here

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2 years ago
Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le
Helen [10]

Answer: \overline{AC}= 12.5

Step-by-step explanation: The triangle ABC and its altitude \overline{BD} is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of \overline{BD}, now we have two similar triangles, which means that ratios of corresponding sides are equal:

\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}

\overline{BD}^{2}=\overline{BC}.\overline{AD} (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}

\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2} (2)

Substituting (2) into (1):

\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}

We want to find f, so:

\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}

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f = 7.5

The length of \overline{AC} is

\overline{AC}=f+5

\overline{AC}=7.5+5

\overline{AC}=12.5

The length of the hypotenuse of triangle ABC is 12.5 units.

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2 years ago
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