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3 years ago

863.141 in expanded form

Mathematics

1 answer:

Neporo4naja [7]3 years ago

4 0

800
+ 60
+ 3
+ 0.1
+ 0.04
+ 0.001

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Simplifying by adding, subtracting, multiplying, or dividing: (2/3)-(2/5)

Volgvan

The answer is 4/15 or .26 with the 6 repeating forever.
Explanation: Least common multiple of 3 and 5 is 15. 2*5=10, 2*3=6. 10/15-6/15=4/15.

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4 years ago

Right inequalities to represent the situations below to get the 10% discount a shopper must spend at least $300 USD to represent

vladimir2022 [97]

Answer:

D≥300

Step-by-step explanation:

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3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

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3 years ago

Convert to standard form. y-5=-3(x+2)

Paul [167]

Answer:

Step-by-step explanation:

y-5=3(x+2)

y-5=3x+6

y-5-6=3x+6-6

y-1=3x

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4 years ago

Joey has a beach ball with a radius of 20 cm. What volume of air will it hold when fully inflated? [Round to nearest tenth.]

nadya68 [22]

It would be D. because the volume of a sphere is 4/2 x pi x radius^3.

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3 years ago

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