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ira [324]
2 years ago
12

NEED HELP ASAP !! WILL MARK BRAINLEAST SHOW WORK TOO !!!

Mathematics
1 answer:
irinina [24]2 years ago
3 0

Step-by-step explanation:

(1 +  \cos(x) )(1 -  \cos(x) )

1  -  \cos {}^{2} (x)

=  \sin {}^{2} (x)

b.

\frac{1}{ \cot {}^{2} (x) }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \frac{ \cos {}^{2} (x) }{ \sin { }^{2} (x) } }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \cot {}^{2} (x) }  -  \frac{   \csc {}^{2} (x)   {} }{ \cot {}^{2} (x) }

\frac{ -  \cot {}^{2} (x) }{ \cot {}^{2} (x) }

- 1

c.

\sec {}^{2} ( \frac{\pi}{2} - x ) )( \sin {}^{2} (x)  -  \sin {}^{4} (x))

( \csc {}^{2} (x) )( \sin {}^{2} (x)  -  \sin {}^{4} (x  )

\csc {}^{2} (x) ( \frac{1}{ \csc {}^{2} (x) }  -  \frac{1}{  \csc {}^{4}  (x) } )

1 -  \frac{1}{ \csc {}^{2} (x) }

1 -  \sin {}^{2} (x)

\cos {}^{2} (x)

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The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

<h3>Reflection of functions and coordinates</h3>

Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates <u>changes position but are negated.</u>

Given the exponential function below

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If the function f(x) is reflected over the x-axis, the resulting function will be

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This means that we are going to negate the function f(x) as shown;

f(x) = -5(0.8)^x

Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

Learn more on reflection here: brainly.com/question/1908648

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PLZ ASAP HURRY PLZ PLZ HURRY!!!!!!!!!
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