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ira [324]
2 years ago
12

NEED HELP ASAP !! WILL MARK BRAINLEAST SHOW WORK TOO !!!

Mathematics
1 answer:
irinina [24]2 years ago
3 0

Step-by-step explanation:

(1 +  \cos(x) )(1 -  \cos(x) )

1  -  \cos {}^{2} (x)

=  \sin {}^{2} (x)

b.

\frac{1}{ \cot {}^{2} (x) }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \frac{ \cos {}^{2} (x) }{ \sin { }^{2} (x) } }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \cot {}^{2} (x) }  -  \frac{   \csc {}^{2} (x)   {} }{ \cot {}^{2} (x) }

\frac{ -  \cot {}^{2} (x) }{ \cot {}^{2} (x) }

- 1

c.

\sec {}^{2} ( \frac{\pi}{2} - x ) )( \sin {}^{2} (x)  -  \sin {}^{4} (x))

( \csc {}^{2} (x) )( \sin {}^{2} (x)  -  \sin {}^{4} (x  )

\csc {}^{2} (x) ( \frac{1}{ \csc {}^{2} (x) }  -  \frac{1}{  \csc {}^{4}  (x) } )

1 -  \frac{1}{ \csc {}^{2} (x) }

1 -  \sin {}^{2} (x)

\cos {}^{2} (x)

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Answer:

60

Step-by-step explanation:

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The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as
geniusboy [140]

Based on the theory, the distance from the starting point to the return point = Arc length = 109.9 feet.

<h3>What is the Length of an Arc?</h3>

The arc length of a circle can be calculated with the radius and central angle using the arc length formula.

Arc length = ∅/360 × 2πr

Since the sector formed is a quarter circle, then ∅ = 90°.

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Distance from the starting point to the return point = arc length.

Arc length = ∅/360 × 2πr =  90/360 × 2π(70)

Arc length =  109.9 feet

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6 0
2 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
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kozerog [31]
C. (4 x 18) - (3 x 12) = p
7 0
3 years ago
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