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Tomtit [17]
2 years ago
11

20) Find the length of a side of a square with a diagonal length of 100 cm.

Mathematics
1 answer:
Andre45 [30]2 years ago
5 0

Answer:

about 7.0710678cm

Step-by-step explanation:

it's a square so the sides are equal.

the diagonal is 100cm

This makes a right triangle with two sides

since the sides are equal, they both are equal to the square root of 50, which is half of 100

the square root of 50 is about 7.0710678cm

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The perimeter of a rectangle is 500 feet. The ratio of the base and height is 3:2. What is the measure of the height ?
nika2105 [10]

Answer:

height=100feet

Step-by-step explanation:

perimeter of a rectangle=p=500 feet

p=2a+2b equation 1

a=height

b=base

we have: b/a=3/2

so a=(2*b)/3

in equation 1 we have:

500=2*((2*b)/3)+2*b

so we have

500=(4*b)/3 + 2*b

500=(4b+6b)/3

500=(10b)/3

500*3=10b

b=(500*3)/10

b=150 feet =base

so

a=(2*150)/3=100 feet = height

8 0
3 years ago
For a company picnic, Matthew ordered a box of fresh-baked gingerbread biscuits and sugar biscuits. He purchased 95 biscuits in
Vilka [71]
____________________________________

5 0
3 years ago
What is s?? <br> A 44° <br> B 35.3° <br> C. 37.9°<br> D. 22°
melisa1 [442]

Answer: Choice B) 35.3 degrees

======================================================

Work Shown:

Apply the law of sines

sin(S)/s = sin(R)/r

sin(S)/16 = sin(120)/24

sin(S) = 16*sin(120)/24

sin(S) = 0.57735026918962

S = arcsin(0.57735026918962)

S = 35.2643896827542

S = 35.3

Make sure your calculator is in degree mode.

7 0
2 years ago
Graph the line with slope -2 passing through the point (1,-4)
lorasvet [3.4K]

the equation for the line is:

y = -2( x + 1 )

4 0
3 years ago
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
3 years ago
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