Help me out guys!!!!!!!

Given the following diagram, find the missing measure.<br>*

BigorU [14]

Option C:

x = 30

Solution:

The given image is a triangle.

angle 1, angle 2 and angle 3 are interior angles of a triangle.

angle 4 is the exterior angle of a triangle.

m∠4 = 2x°, $m\angle2=\frac{4}{3}x^\circ$ , m∠3 = 20°

Exterior angle theorem:

<em>In triangle, the measure of exterior angle is equal to the sum of the opposite interior angles.</em>

By this theorem,

m∠4 = m∠2 + m∠3

$$2x^\circ=\frac{4}{3}x^\circ+20^\circ$

Subtract $\frac{4}{3}x^\circ$ on both sides of the equation.

$$2x^\circ-\frac{4}{3}x^\circ=20^\circ$

To make the denominator same and then subtract.

$$\frac{6}{3}x^\circ -\frac{4}{3}x^\circ=20^\circ$

$$\frac{2}{3}x^\circ =20^\circ$

Multiply by $\frac{3}{2}$ on both sides of the equation.

x° = 30°

x = 30

Hence option C is the correct answer.

6 0

3 years ago

1.

Taya2010 [7]

Answer:

-7x+7y=-49 matches this graph.

maddymcg408 avatar

The correct option is (B)

Step-by-step explanation: We are given to match the graph with its correct equation.

From the graph, we note that

there is a straight line where the points (7, 0) and (0, -7) lie on it.

So, the slope of the line is given by

Since the line passes through the point (7, 0), so its equation will be

Thus, the required equation of the graphed line is

Option (B) is CORRECT.

Step-by-step explanation:

-7x+7y=-49 matches this graph.

maddymcg408 avatar

The correct option is (B)

Step-by-step explanation: We are given to match the graph with its correct equation.

From the graph, we note that

there is a straight line where the points (7, 0) and (0, -7) lie on it.

So, the slope of the line is given by

Since the line passes through the point (7, 0), so its equation will be

Thus, the required equation of the graphed line is

Option (B) is CORRECT.

maddymcg408 avatar

jr3974 avatar

jr3974

10/31/2017

Mathematics

College

answered

Match the graph with its equation.

7x + 7y = 0

7x – 7y = –49

7x + 7y = 49

–7x +7y = –49

2

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maddymcg408 avatar

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4 0

3 years ago

Evaluate the given integral by making an appropriate change of variables, where r is the rectangle enclosed by the lines x - y =

vova2212 [387]

$\begin{cases}u=x-y\\v=x+y\end{cases}$

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial u}{\partial y}\\\\\dfrac{\partial v}{\partial x}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&-1\\1&1\end{bmatrix}$
$\implies\det\mathbf J=2$

The area of the region is then given by

$\displaystyle\iint_R\mathrm dA=\int_{u=0}^{u=7}\int_{v=0}^{v=6}2\,\mathrm dv\,\mathrm du=84$