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Romashka-Z-Leto [24]
3 years ago
5

Someone please help asap !!!!!

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

D.  QR > PR > PQ

Step-by-step explanation:

The side length of the triangle is proportional to angle measures so we need to determine the angle measure first:

Angle P = 99

Angle Q = 41

Angle K = 40 so now the longest side length would be the one that sees biggest angle, angle P.

QR > PR > PQ

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What percent of 752 is 25?
wariber [46]
25 is about 3.32% of 752.
5 0
3 years ago
a cell phone company has a basic monthly plan of $40plus $0.45 for many minutes ised over 700. John was charged a total of $48.1
jonny [76]
Cost of month plan = $40

Cost of minutes used = $0.45 after 700 minutes

Total cost = $48.10

Let x be the total minutes used
Total cost = 40 + 0.45(x - 700)

------------------------------------------------------------------
Form the equation and solve x
------------------------------------------------------------------
40 + 0.45(x - 700) = 48.10
40 + 0.45x - 315 = 48.10
0.45x - 275 = 48.10
0.45x = 48.10 + 275
0.45x = 323.10
x = 323.10 ÷ 0.45
x = 718

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Answer: John had used 718 mins this month
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8 0
4 years ago
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Vedmedyk [2.9K]
Huh come again? I’m not sure what you just said
6 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
Which of these is an example of a continuous random variable?
dalvyx [7]
B.Number of eye blinks in a minute.
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D.Dogs get placed in a kennel and have a set ammount.
4 0
3 years ago
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