Question

Someone solve this for me please

Answer 1

Answer:

x=-1, x=3 e x=2i, x=-2i

Step-by-step explanation:

Solve for x over the real numbers:

x^4 - 2 x^3 + x^2 - 8 x - 12 = 0

The left hand side factors into a product with three terms:

(x - 3) (x + 1) (x^2 + 4) = 0

Split into three equations:

x - 3 = 0 or x + 1 = 0 or x^2 + 4 = 0

Add 3 to both sides:

x = 3 or x + 1 = 0 or x^2 + 4 = 0

Subtract 1 from both sides:

x = 3 or x = -1 or x^2 + 4 = 0

Subtract 4 from both sides:

x = 3 or x = -1 or x^2 = -4

x^2 = -4 has no solution since for all x on the real line, x^2 >=0 and -4<0:

Answer: |

| x = 3 or x = -1