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icang [17]
3 years ago
14

Can someone help me with this I’m having a hard time with HW and it’s due tmrw.

Mathematics
1 answer:
Nady [450]3 years ago
8 0
In figure A, you would want to go up 2 and across right 6 to get to A'. In figure 2 you can go up 1 then across right 2.
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Help!!! I just need Help on number 6 please!!!!!!!! ASAP!!!
PtichkaEL [24]

Answer:

3

Step-by-step explanation:

\sqrt{12} =3.46 (2 decimal places)

If you want to arrange the tiles into a square, you will need 3.46 in each row/column.

This is physically impossible, hence you round it down to 3.

(If you round it up, you won't have enough tiles since 4*4=16)

Thus, the square area will be 3*3=9

Tiles left: 12-9=3

6 0
3 years ago
Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1). Include your work in y
lys-0071 [83]
First find the slope, 
m=(y2-y1)/(x2-x1)=(1-(-9))/(7-6)=10
Next, use the point slope form to find the equation:
L : y-y1=m(x-x1) => y-1=10(x-7) 
    [in point slope form, point is (7,1), slope=m=10 ]


5 0
3 years ago
A giant hummingbird can flap its wings at a rate of 13 flaps per second, how many times
antoniya [11.8K]

Answer:

780 flaps per second

Step-by-step explanation:

just multiply 13×60

8 0
3 years ago
The sum of three consecutive odd integers is 207. What are the​ integers?
nikdorinn [45]
Hey!

It says that it is the sum of 3 consecutive odd integers right?

So then we give these numbers some variables to work with like so...

x = 1st number
x + 2 = 2nd number
x + 4 = 3rd number

now set all of them equal to 207

x + x + 2 + x + 4 = 207
3x + 6 = 207
3x = 201
<u>x = 67</u><u />                     <u>x + 2 = 69</u><u />              <u /><u />   <u>x + 4 = 71
</u>
<u>
</u>


4 0
3 years ago
Given the graph of the function f(x) shown below, find the average rate of change of the function f(x) on the interval [5,15].
monitta

Answer: wheres the graph

Step-by-step explanation: In order to answer this question, I need the picture of the graph please.

6 0
3 years ago
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