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2 years ago

Can someone help me with this I’m having a hard time with HW and it’s due tmrw.

Mathematics

1 answer:

Nady [450]2 years ago

8 0

In figure A, you would want to go up 2 and across right 6 to get to A'. In figure 2 you can go up 1 then across right 2.

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Find the equation of the line passing through the points (6,3) and (-4,3)<br> Y=

Molodets [167]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Equation of line passing through given points :

Let's proceed with two point form ~

$\qquad \sf \dashrightarrow \: y - y1 = \cfrac{y2 - y1}{x2 - x1} (x - x1)$

Assume :

$\qquad \sf \dashrightarrow \: y - 3= \cfrac{3 - 3}{ - 4 - 6} (x - 6)$

$\qquad \sf \dashrightarrow \: y - 3= \cfrac{0}{ - 10} (x - 6)$

$\qquad \sf \dashrightarrow \: y - 3 = 0$

$\qquad \sf \dashrightarrow \: y = 3$

So, the equation of required line is : y = 3 ~

5 0

1 year ago

Find the radian measure of an angle of -280°

Bingel [31]

To convert an angle from degrees to radians, multiply by π/180°.

Your angle is
(-280°)*(π/180°) = -14π/9

The appropriate choice is ...
B) (-14π/9)

4 0

3 years ago

The Height of a ramp is 11 inches and the length of its slanted side it 61 inches. What is the length of the base of the ramp?

o-na [289]

Triangle:

39 degrees, 33 degrees, 108 degrees

Side opposite the 108 degrees is 360 feet.

length asked for is d

Hope this helped you! Brainliest? :)

5 0

3 years ago

Pls help ur girl out with math

Zinaida [17]

135 degrees is your answer

8 0

2 years ago

A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn

tester [92]

Answer:

a) We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

b) $z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

c) $p_v =2*P(z$

d) Null hypothesis: $p=0.35$

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

$\hat p=\frac{522}{1562}=0.334$ estimated proportion of people who have heard of a new electronic reader

$p_o=0.35$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

Part b

The statistic for this case is given :

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

$p_v =2*P(z$

Part d

The null hypothesis for this case would be:

Null hypothesis: $p=0.35$

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0

3 years ago