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3 years ago

Please help asap due today !!

Mathematics

2 answers:

juin [17]3 years ago

8 0

Answer:

Option B

Step-by-step explanation:

$3ab {}^{2} {c}^{3} \sqrt{5a} \\$

$\sqrt{3ab {}^{2} {c}^{3} \times 3ab {}^{2} {c}^{3} \times 5a } \\$

$\sqrt{9a {}^{2} b {}^{4} {c}^{6} \times 5a } \\$

$\sqrt{45a {}^{3} b {}^{4} {c}^{6} } \\$

Thus, The answer is √45a³b⁴c⁶

-TheUnknownScientist 72

Allisa [31]3 years ago

7 0

Answer: B

Step-by-step explanation:

Just square the variables outside the square root and multiply them with 5a.

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4 years ago

64 POINT QUESTION √(5-2x) - √(2-x) = 1

Ivanshal [37]

Answer:

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Step-by-step explanation:

The easiest way is to guess. We know that you can't have a square root of a negative number. This constrains x between negative infinity to 2. Testing 2 and -2, we see that it satisfy the equation.

The more systematic approach is shown below

$\sqrt{5-2x}-\sqrt{2-x}=1 \\\sqrt{5-2x}-\sqrt{2-x}+\sqrt{2-x}=1+\sqrt{2-x} \\\sqrt{5-2x} = 1+\sqrt{2-x}$

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