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lakkis [162]
2 years ago
8

he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis a

nd also on the y axis. Line A passes through the ordered pairs negative 3, 4 and 9, negative 2. Line B passes through the ordered pairs 2, 8 and 8, negative 8. Line C passes through the ordered pairs negative 3, negative 4 and 4, 6. Line D passes through the points 2, negative 2 and 5 and 6. Which set of equations has (5, 0) as its solution? A and B C and D B and D A and D
Mathematics
1 answer:
denis23 [38]2 years ago
6 0

The set of equation that is known to have 5 and 0 as solutions is A and B.

<h3>How to solve for the system of equations.</h3>

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

Read more on graphs here:

brainly.com/question/10465970

#SPJ1

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Answer:

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Step-by-step explanation:

If x = 6 the problem should look like this:

2 (x) + 8 = y -> place the 6 where x is.

2 (6) + 8 = y -> remember () means to multiply.

2 times 6 , add 8 , equals y

12 + 8 =y -> 12 +8 equals 20

20 = y

I hope this helps!!

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2 years ago
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Ainat [17]
50 + 14. Hope this helps!
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Please help I don't understand!
Vlad1618 [11]

Answer:

False

Step-by-step explanation:

The <em>cross-product</em> property is used, not the ratio-quotient property.

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Which of these is an example of a literal equation?
Ahat [919]

Answer: B. 12=9+3x

Step-by-step explanation:

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Answer:

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One potential confusion students may have follows from the subtle difference between what the car is doing and the idea of slope as the ratio between the change in vertical distance on the graph and the change in horizontal distance on the graph. Because the car is traveling one mile on a down-hill slope, the situation could be represented as a right triangle with a hypotenuse of 5,280 ft and a leg of 250 ft; using the Pythagorean Theorem they would find that the other leg is approximately 5,274 ft. Following through on this interpretation, a student might conclude that the car travels a horizontal distance of approximately 5,274 ft for every 250 ft in vertical distance and arrive at a slope of approximately -0.047. While this is, in some sense, the slope of the hill, it is not the slope of the function as described. This interpretation yields numbers that are very close to the situation described in the task, yet conceptually different since the distance traveled by the car would now be expressed in terms of horizontal distance traveled as opposed to distance along the slope of the hill to compute the elevation. If students do indeed pursue this line of reasoning, the task provides an opportunity to compare and contrast the graph of the function and what it represents with a drawing of the hill and the vertical and horizontal distances traversed with each mile down the slope.

Step-by-step explanation:

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