Answer:
D. The typical value is greater in set A. The spread is greater in set B.
Step-by-step explanation:
The typical value is greater in set A.
[] We can see that the red arrow already shows this, but the average (add up all the numbers and divide by number or numbers) in set A is greater than in set B as 7 > 6.
The spread is greater in set B.
[] The spread can also be thought of as the range (largest number - smallest number) so the spread is greater than B since 7 > 3.
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The ordered pair is (-1/7, 0)
Values in increasing order
<span>42 </span>
<span>46 </span>
<span>51 </span>
<span>53 </span>
<span>66 </span>
<span>70 </span>
<span>70 </span>
<span>90 </span>
<span>Lower quartile : There are 8 observations </span>
<span>If there are in observations, compute the lower quartile as follows: </span>
<span>if n/4 is an integer, compute the lower quartile as </span>
<span>(x[n/4]+x[n/4+1])/2 :: (x[8/ 4]+x[8 /4 +1])/2 </span>
<span>if n/4 is not an integer, compute the lower quartile as </span>
<span>x[k], where k is the smallest integer exceeding n/4:: 2 = 2 </span>
<span>Lower Quartile : Average of observations 2 and 3 is -- </span>
<span>= (46+51)/2 = 48</span>
<span>the twentieth odd number is 39</span>
Answer:
Option C. 1020
Step-by-step explanation:
From the question given above,
512 + 256 +... + 4 =?
We'll begin by calculating the number of terms in the sequence. This can be obtained as follow:
First term (a) = 512
Common ratio (r) = 2nd term / 1st term
Common ratio (r) = 256 /512
Common ratio (r) = 1/2
Last term (L) = 4
Number of term (n) =?
Tₙ = arⁿ¯¹
L = arⁿ¯¹
4 = 512 × (1/2)ⁿ¯¹
Divide both side by 512
4 / 512 = (1/2)ⁿ¯¹
1/128 = (1/2)ⁿ¯¹
Express 128 in index form with 2 as the base
1/2⁷ = (1/2)ⁿ¯¹
(1/2)⁷ = (1/2)ⁿ¯¹
Cancel 1/2 from both side
7 = n – 1
Collect like terms
7 + 1 = n
n = 8
Thus, the number of terms is 8
Finally, we shall determine the sum of the series as follow:
First term (a) = 512
Common ratio (r) = 1/2
Number of term (n) = 8
Sum of 8th term (S₈) = ?
Sₙ = a[1 – rⁿ] / 1 – r
S₈ = 512 [1 – (½)⁸] / 1 – ½
S₈ = 512 [1 – 1/256] ÷ ½
S₈ = 512 [255/256] × 2
S₈ = 2 × 255 × 2
S₈ = 1020
Thus, the sum of the series is 1020.