40 hours * 52 weeks = 2080 hours total worked that year.
2080 hours * 25.21 paycheck = 52,436.80
In reality you would have to subtract out holidays, any vacation, any sick days and taxes. All of that information varies by location and company.
Answer:
3003
Step-by-step explanation:
It is going to be 15C5
Answer: X = y - yi - 7i
Y = (x + 7i)/(1 - i)
Step-by-step explanation: for the case of (X) you only need to pass the 7i to the other side with the subtraction sign (-7i), then we get this equation:
x + 7i = y − yi
X = y - yi - 7i
in the case of the (Y), first we select the common multiple.
y - yi = y(1 - i)
if we replace it in the original expression, we get the following equation:
x + 7i = y(1 - i)
after that you can pass the value (1 - i) to the other side dividing,
Y = (x + 7i)/(1 - i)
Answer: The number 12 represents admission charge in Mariana's equation.
Step-by-step explanation:
As per given ,
Total cost = ( Charge per ticket) (Number of tickets) + (Admission fees) (i)
For x = Number of tickets, the total cost (c) for a day at the amusement park is given as
(ii)
Here, 12 = Admission fees [Comparing (i) and (ii)]
Hence, the number 12 represents admission charge in Mariana's equation.
Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
