Question

Y= 2x-1 is a tangent to y=x^2. Name the point of tangency,

Answer 1

Answer:

Point of tangency is $x=1$ or $(1,1)$

Step-by-step explanation:

You don't really need to use Calculus here. You can just set each equation to each other and solve for x (the point of tangency):

$x^2=2x-1$

$x^2-2x+1=0$

$(x-1)(x-1)=0$

$x=1$

Therefore, the point of tangency is $x=1$ or $(1,1)$