1 3 1×3 3
--- × --- = ------ = ----
2 4 2×4 8
5 5 5×5 25
--- × ---- = --------- = -------
6 7 6×7 42
hope is understandably
Answer:
2 RootIndex 4 StartRoot 4 EndRoot
Step-by-step explanation:
we have

Decompose the number 64 in prime factors

substitute
![64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%282%5E%7B4%7D2%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D2%5E%7B%5Cfrac%7B4%7D%7B4%7D%7D2%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
Answer:
7/16
Step-by-step explanation:
137,638
+52,091
-------
189,729 ⇨ 189,730
Only cabinet with two silver coins is cabinet B.
The chance of choosing cabinet B is 1/3.
Thus, there is a 1/3 chance of the two cabinets contain 2 silver coins.