Question

Bill is 15 years older than Paul. Paul is 7 years older than half Milo's age. The sum of all three ages is 85. How old is Bill?

Answer 1

Answer:

Step-by-step explanation:

Let Milo's age = x

$Paul's \ age =\dfrac{1}{2}x+7\\\\\\Bill's \ age = \dfrac{1}{2}x + 7 +15 =\dfrac{1}{2}x+22$

Sum of all three ages = 85

$x +\dfrac{1}{2}x+7 +\dfrac{1}{2}x+22 = 85\\x +\dfrac{1}{2}x+\dfrac{1}{2}x+7+22 =85\\2x+29=85\\ 2x = 85-29\\\\ 2x = 56\\\\ x = \dfrac{56}{2}\\\\x =28 \ years\\\\\\Bill's \ age =\dfrac{1}{2}x+22 =\dfrac{1}{2}*28+22\\\\\\= 14+22$

Bill's age = 36 years

Answer 2

Answer:

Bill is 36

Step-by-step explanation:

Bill, Paul, and Milo are represented as b, p, m

b = 15+p; p = 1/2m + 7; b + p + m = 85

b = 36, m = 28, p = 21

Therefore Bill is 36 y/o