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IceJOKER [234]
3 years ago
13

HELP GIVING BRAINLIEST Carlene is selling T-shirts for a fundraiser. The T-shirts cost $20.50 each. To date, she has raised $900

. Her goal is to raise more than $9,100. How many more T-shirts, x, does Carlene need to sell to reach her goal?
Select the number line that includes the fewest number of T-shirts Carlene can sell and still meet her goal.
Mathematics
1 answer:
Valentin [98]3 years ago
8 0

FYI:

Sorry, I can't answer your second question because I can't see any number-lines in your question. But yes, I can answer the first one.

Answer:

400 T-Shirts

Step-by-step explanation:

If each T-Shirt is $20.50, that means that Carlene has to sell lots of them in order to earn the amount of money she wants. So, to find how many T-Shirts she needs to sell in order to get $9,100, we have first remove $900 dollars from the $9,100, because she ALREADY earned it!

9,100-900=8,200

Now we have to divide $8,200 by $20.50. like this...

8,200÷20.50=400

Now, that's our answer. 400.

<h2>Carlene has to sell 400 more T-Shirts in order to earn to her goal!</h2><h2></h2>

Thank You! Please mark me brainliest so that I can get encouraged to make more great answers like this one!

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F=\frac{s^2_2}{s^2_1}=\frac{5.4}{2.3}=2.348

p_v =2*P(F_{15,15}>2.348)=0.109

And we can use the following excel code to find the p value:"=2*(1-F.DIST(2.348,15,15,TRUE))"

Since the p_v > \alpha we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation is different between the two groups at 10% of significance.  

Step-by-step explanation:

Assuming the following question :"The accounting department analyzes the variance of the weekly unit costs reported by two  production departments. Asample of 16 cost reports for each of the two departments shows  cost variances of 2.3 and 5.4, respectively. Is this sample sufficient to conclude that the two  production departments differ in terms of unit cost variance? Use α= .10."

Data given and notation  

n_1 = 16 represent the sampe size for sample 1

n_2 =16 represent the sample size for sample 2

s^2_1 = 2.3 represent the sample variance for sample 1

s^2_2 = 5.4 represent the sample variance for sample 2

\alpha=0.1 represent the significance level provided

Confidence =0.9 or 9%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Solution to the problem  

System of hypothesis

We want to test if the variation is equal for both groups or no, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

Calculate the statistic

Now we can calculate the statistic like this:

F=\frac{s^2_2}{s^2_1}=\frac{5.4}{2.3}=2.348

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

P value

Since is a bilateral test the p value is given by

p_v =2*P(F_{15,15}>2.348)=0.109

And we can use the following excel code to find the p value:"=2*(1-F.DIST(2.348,15,15,TRUE))"

Conclusion

Since the p_v > \alpha we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation is different between the two groups at 10% of significance.  

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