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IceJOKER [234]
3 years ago
13

HELP GIVING BRAINLIEST Carlene is selling T-shirts for a fundraiser. The T-shirts cost $20.50 each. To date, she has raised $900

. Her goal is to raise more than $9,100. How many more T-shirts, x, does Carlene need to sell to reach her goal?
Select the number line that includes the fewest number of T-shirts Carlene can sell and still meet her goal.
Mathematics
1 answer:
Valentin [98]3 years ago
8 0

FYI:

Sorry, I can't answer your second question because I can't see any number-lines in your question. But yes, I can answer the first one.

Answer:

400 T-Shirts

Step-by-step explanation:

If each T-Shirt is $20.50, that means that Carlene has to sell lots of them in order to earn the amount of money she wants. So, to find how many T-Shirts she needs to sell in order to get $9,100, we have first remove $900 dollars from the $9,100, because she ALREADY earned it!

9,100-900=8,200

Now we have to divide $8,200 by $20.50. like this...

8,200÷20.50=400

Now, that's our answer. 400.

<h2>Carlene has to sell 400 more T-Shirts in order to earn to her goal!</h2><h2></h2>

Thank You! Please mark me brainliest so that I can get encouraged to make more great answers like this one!

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The confidence interval for the mean is given by the following formula:  

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Lower= 0.11-0.04 = 0.07

Upper= 0.11+0.04 = 0.15

And for this case we have the following info:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

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