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n200080 [17]
2 years ago
7

24 students in a class took an algebra test.

Mathematics
2 answers:
Vlada [557]2 years ago
8 0

Answer:

75 % passed

25 % did NOT pass

Step-by-step explanation:

vodomira [7]2 years ago
8 0
75% passed
25% did not pass
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Celina and Richard spend a certain amount of money from their money box each month to buy plants.
loris [4]

Answer:

100

Step-by-step explanation:

5 0
3 years ago
Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if
Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

​ This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

5 0
3 years ago
Imagine that the average weight of a total of 500 girls in a high school is 35kg. Tom randomly sampled 10 girls and measured the
Naddik [55]

Answer:

The sample 2 has a lowest value of SE corresponding to the least sample variability.

Step-by-step explanation:

As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows

The data is as attached with the solution. From this data

Sample 1 has a mean of 34 and a SE of 5

Sample 2 has a mean of 30 and a SE of 2

Sample 3 has a mean of 26 and a SE of 3

Sample 4 has a mean of 38 and a SE of 5

As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .

So the sample 2 has a lowest value of SE corresponding to the least sample variability.

4 0
4 years ago
Using technology, determine the semi-annual payment on a 6 year loan of $19,264 at 7.2% compounded semi-annually. Round you answ
Temka [501]
D is the corrrect answer 
5 0
3 years ago
Read 2 more answers
On a Saturday, Saul can cut 4 lawns in 6 hours. If Mitch can mow lawns at the same rate, how long will it take him to mow 9 lawn
Charra [1.4K]
Mowing 4 lawns in 6 hours gives a mowing rate of 6/4 = 1.5 hours per lawn.
To mow 9 lawns, you need 1.5*9 = 13.5 hours.

The answer is B.
6 0
3 years ago
Read 2 more answers
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