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n200080 [17]
2 years ago
7

24 students in a class took an algebra test.

Mathematics
2 answers:
Vlada [557]2 years ago
8 0

Answer:

75 % passed

25 % did NOT pass

Step-by-step explanation:

vodomira [7]2 years ago
8 0
75% passed
25% did not pass
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Simplifying
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9. What's the least common multiple (LCM) of 2, 6, and 8?
algol [13]

Answer:

24

Step-by-step explanation:

The LCM or least common multiple of these numbers is 24

To get 24, you list all the multiple of these numbers until they all share at least one

So

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, <u>24</u>

6, 12, 18, <u>24</u>

8, 16, <u>24</u>

They all share 24 so this is the LCM

Hope this helps

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3 0
3 years ago
Find three pairs of equivalent fractions
Mrrafil [7]
1/3 : 2/6
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7 0
3 years ago
Read 2 more answers
48 divided by blank = 8
kati45 [8]
Blank=6
6 times 8  =48
because it is like 6 8s ok so 8+8+8+8+8+8=48   
                                                     or
                                          6+6+6+6+6+6+6+6=48     
try it on paper and you will see I am right :)

5 0
3 years ago
5. A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4pci or less. Th
zysi [14]

Complete Question

A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4 pci or less. The scientist tests the composition for 36 days finding an average concentration of 4.4 pci with a sample standard deviation of 1 pci.

a) In testing the scientist's belief, write the appropriate hypotheses:

           H_o:                   Ha:

b) What decision should be made?

Answer:

a

The null hypothesis is  H_o :  \mu  \le  4 \  pci

The  alternative  hypothesis is H_a  :  \mu  >  4 \ pci

b

There is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu  =  4 \ pci

    The sample size n  =  36 \ days

     The  sample  mean is  \= x  =  4.4 \  pci

     The  standard deviation is  \sigma  =  1 \ pci

       The  level  of significance is  \alpha =  0.05

The null hypothesis is  H_o :  \mu  =  4 \  pci

The  alternative  hypothesis is H_a  :  \mu  >  4 \ pci

  Generally the test statistics is mathematically represented as

          t =  \frac{ \= x  -  \mu }{ \frac{ \sigma}{ \sqrt{n} } }

=>      t =  \frac{ 4.4  -  4 }{ \frac{ 1}{ \sqrt{36} } }

=>      t =  \frac{ 4.4  -  4 }{ \frac{ 1}{ \sqrt{36} } }

=>      t =2.4

The  p-value  is mathematically represented as

      p-value  =  P(Z >  2.4  )

From the  z-table  

          P(Z >  2.4  )  =  0.008

    p-value  =0.008

So from this obtained value  we see that

     p-value <  \alpha so we reject the null hypothesis

Hence we can conclude that there is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

4 0
3 years ago
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