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2 years ago

Please help me solve #9, and please 10

Mathematics

1 answer:

german2 years ago

6 0

Answer:

#9. y = -250x

#10. y = -2500, x = 100

Step-by-step explanation:

y = mx +b

y: y-value

m: slope

x: x-value

b: y-intercept

since your answer for #8 is -250, the slope would be -250 or m would be -250

y = -250x+b

now to solve for b, we take one of the points and plug it in, any works, but we'll use (1,-250)

plug in the points

-250 = -250(1)+b

solve for b

b = 0

thus the equation is y = -250x + 0 or y = -250x

#10 plug in x values and y values into equation to get answer

x = 10 -> y = -250(10) = -2500

y = -25,000 -> -25,000 = -250x

x = -25,000/-250

x = 100

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3 years ago

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Justification three common tangents

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Three common tangents is illustrated when two circles touch each other externally at one point and they'll have three tangents.

<h3>How to illustrate the information?</h3>

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1 year ago

A TV is on sale for $125 off. The sale price is $875.

Evgesh-ka [11]

Let's call the original price $o$ and the sale price $s$ . Given the information in the problem, we can say:

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(The sale price subtracted from the original price is the sale on the product, which we know is 125.)

We know the value of $s$ , which is 875. If we substitute this into the equation we found, we can find $o$ , as shown below:

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7 0

3 years ago

Point A is located at (3,6). The midpoint of line segment AB is point C(11,13). What are the coordinates of point B? Use the mid

lesya692 [45]

Answer: The coordinates of point B are (19 , 20).

Step-by-step explanation:

The mid point (x,y) of line joining (a,b) and (c,d) is given by :-

$(x,y)=(\dfrac{a+c}{2},\dfrac{b+d}{2})$ (1)

Given : Point A is located at (3,6). The midpoint of line segment AB is point C(11,13).

Let the coordinates of point B are (a,b) m, the according to (1) , we have

$(\dfrac{3+a}{2},\dfrac{6+b}{2})=(11,13)\\\\\Rightarrow\ \dfrac{3+a}{2}=11\ \ ,\ \ \dfrac{6+b}{2}=13\\\\\Rightarrow\ 3+a=22\ \ ,\ \ \ 6+b=26\\\\\Rightarrow\ a=19,\ \ b= 20$

Hence, the coordinates of point B are (19 , 20).

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3 years ago

In each figure below find m∠1 and m∠2, if a||b. Show your work with statements.

quester [9]

ANSWER

$m < \: 1 = 80 \degree$

$m < \: 2= 70 \degree$

EXPLANATION

Since

$a || b$
line s and t are both transversals.

This implies that,

$m < \: 1 \: and \: 80 \degree$

are alternate angles.

Alternate angles are equal. Therefore,

$m < \: 1 = 80 \degree$

Also,

$m < \: 2= 70 \degree$

because corresponding angles are equal.

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3 years ago