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Montano1993 [528]
2 years ago
10

Please help me solve #9, and please 10

Mathematics
1 answer:
german2 years ago
6 0

Answer:

#9. y = -250x

#10. y = -2500, x = 100

Step-by-step explanation:

y = mx +b

y: y-value

m: slope

x: x-value

b: y-intercept

since your answer for #8 is -250, the slope would be -250 or m would be -250

y = -250x+b

now to solve for b, we take one of the points and plug it in, any works, but we'll use (1,-250)

plug in the points

-250 = -250(1)+b

solve for b

b = 0

thus the equation is y = -250x + 0 or y = -250x

#10 plug in x values and y values into equation to get answer

x = 10 -> y = -250(10) = -2500

y = -25,000 -> -25,000 = -250x

x = -25,000/-250

x = 100

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kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

8 0
4 years ago
How to write 8ft and 26in in standard notation
zmey [24]

The length in standard notation is 2.17 + 8 = 10.17 ft

<h3>How to write in standard notation? </h3>

A standard notation is a form of writing a given number, an equation, or an expression in a form that follows certain rules.

For example 9.5 billions years can be represented as follows;

9,500,000,000 years.

Therefore,  let's write 8 ft and 26 inches in standard form.

12 inches = 1 ft

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cross multiply

length(ft) = 26 / 12

length(ft) = 2.16666666667

length(ft) = 2.17 ft

Therefore, the length in standard notation is 2.17 + 8 = 10.17 ft

learn more on standard notation here: brainly.com/question/14414107

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8 0
2 years ago
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3 years ago
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faltersainse [42]

Answer:

The idea is to transform the expression by multiplying (\sqrt{x + 1} - \sqrt{x}) with its conjugate, (\sqrt{x + 1} + \sqrt{x}).

Step-by-step explanation:

For any real number a and b, (a + b)\, (a - b) = a^{2} - b^{2}.

The factor (\sqrt{x + 1} - \sqrt{x}) is irrational. However, when multiplied with its square root conjugate (\sqrt{x + 1} + \sqrt{x}), the product would become rational:

\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}.

The idea is to multiply \sqrt{x}\, (\sqrt{x + 1} - \sqrt{x}) by \displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} so as to make it easier to take the limit.

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The order of x in both the numerator and the denominator are now both (1/2). Hence, dividing both the numerator and the denominator by x^{(1/2)} (same as \sqrt{x}) would ensure that all but the constant terms would approach 0 under this limit:

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}.

By continuity:

\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}.

8 0
3 years ago
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So your answer is 6 hours

Hope this helped:))

3 0
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