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denis-greek [22]
4 years ago
11

...........................

Mathematics
1 answer:
Taya2010 [7]4 years ago
4 0
Hello what are you asking please comment below and I will help you there
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The greatest common factor of 12 and 26 pls explain the steps
Softa [21]
2

12= 2 * 6
26= 2 * 13, gcf is 2




Mark brainliest please mark


Hope this helps you
5 0
3 years ago
Read 2 more answers
Which equation represents a proportional relationship? y=−2x y=32x y = 4x + 3 y=2(x+1)
Liono4ka [1.6K]

Answer:

Option B is correct.

y =32x represents a proportional relationship.

Step-by-step explanation:

If two quantities are said to have a proportional relationship if they vary in such a way that one of the quantities is a constant multiple of the other i.e,

y = |k| y where |k| is constant proportionality.

By definition :

y =32x  where k =32 is constant ,  represents a proportional relationship.



3 0
3 years ago
Read 2 more answers
What equation(s) represent joint variations? check all that apply c=2pi z=3x/y y=3x+2 w=abc/4 v=lwh
Alinara [238K]

Answer:

Step-by-step explanation:

Joint variations occurs when one variable depends on the value of two or more variables. The variable varies directly or indirectly with the other variables combined together. The other variables are held constant. From the given examples, the equation(s) that represent joint variations are

1) z = 3x/y

z varies directly with x and inversely with y.

2) w = abc/4

w varies inversely with a,b and c. 4 is the value of the constant of variation.

7 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
The least common multiple of two numbers is 40. The difference of the two numbers is 2. What are the numbers?
Olin [163]
8 and 10 because 8 x 5 equals 40 and 10 x 4 equals 40. and 10 minus 8 is two
4 0
3 years ago
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