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Nutka1998 [239]

2 years ago

13

A zoo has 65 birds now. It adopted 17 new birds last week. How many birds did the zoo have before it adopted the new birds? Writ

e and solve an equation. Then write the answer.

1 answer:

svetoff [14.1K]2 years ago

6 0

Correct me if I’m wrong but I believe the answer is 48

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19. James has a desk job and would like to become more fit, so he purchases a

Neko [114]

Answer:

The correct answer is option (C)-0.245 = 2.160(0.205)

Step-by-step explanation:

Solution

Given that:

The slope = - 0.245

The size sample = n = 15

The standard error = 0.205

The confidence level = 95

The Significance level= α = (100- 95)% = 0.05

Now,

The freedom of degree = n-2 = 15 -2= 13

Thus,

the critical value = t* = 2.16

By applying Excel = [TINV (0.05, 13)]

The Margin of error is = t* (standard error)

=2.16 *0.205

= 0.4428

8 0

2 years ago

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Shtirlitz [24]

Answer:

The number c is 2.

Step-by-step explanation:

Mean Value Theorem:

If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

In this problem, we have that:

$f(x) = x, a = 0, b = 4$

So $f(c) = c$

----------

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

$c = \frac{1}{4-0}\int\limits^0_4 {x} \, dx$

$c = \frac{1}{4-0}*8$

$c = 2$

The number c is 2.

3 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago

164,215 rounded to the nearest hundred thousand

ruslelena [56]

The answer is 200,000

3 0

3 years ago

Read 2 more answers

3. Ahmed wants to buy a new carpet for his house. The cost of the carpet is $240. One day the carpet shop has a special offer of

Mamont248 [21]

Answer:

After using the offer the carpet would cost Ahmed $180.

Step-by-step explanation:

Given:

Cost of the carpet = $240

Discount percent = 25%

We need to find the cost of the carpet after discount.

Solution:

First we will find the Discount cost.

Now we know that;

Discount cost is equal to Discount percent multiplied by Cost of the carpet divided by 100.

framing in equation form we get;

Discount cost = $\frac{25}{100}\times 240 = \$60$

Now we will find the Cost of the carpet after discount.

Now we know that;

Cost of the carpet after discount is equal to Cost of the carpet minus Discount cost.

framing in equation form we get;

Cost of the carpet after discount = $\$240-\$60= \$180$

Hence After using the offer the carpet would cost Ahmed $180.

6 0

3 years ago