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Katyanochek1 [597]
2 years ago
10

PLEEEEEEEEASE HELPPPP i have to do this last problem but i only have 2 minutes left!!!!!!!!!!

Mathematics
2 answers:
mihalych1998 [28]2 years ago
7 0
There’s 40 ticks so place it on each 5
Cerrena [4.2K]2 years ago
3 0

Answer:

there's 40 ticks so place it along each five

Step-by-step explanation:

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If I buy a 7.2 oz bag of cheese-its for $1.99 how much will I be paying for 1 oz?
o-na [289]

Answer:

i think 0.28

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Expand the function f(x)=(3x+2)^4 with the binomial theorem, not factored
lozanna [386]

Step-by-step explanation:

Enter a problem...

Algebra Examples

Popular Problems

 

Algebra

 

Expand using the Binomial Theorem (3x+2)^4

(3x+2)4(3x+2)4

Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an−kbk)(a+b)n=∑k=0n⁡nCk⋅(an-kbk).

4∑k=04!(4−k)!k!⋅(3x)4−k⋅(2)k∑k=04⁡4!(4-k)!k!⋅(3x)4-k⋅(2)k

Expand the summation.

4!(4−0)!0!⋅(3x)4−0⋅(2)0+4!(4−1)!1!⋅(3x)4−1⋅(2)+4!(4−2)!2!⋅(3x)4−2⋅(2)2+4!(4−3)!3!⋅(3x)4−3⋅(2)3+4!(4−4)!4!⋅(3x)4−4⋅(2)44!(4-0)!0!⋅(3x)4-0⋅(2)0+4!(4-1)!1!⋅(3x)4-1⋅(2)+4!(4-2)!2!⋅(3x)4-2⋅(2)2+4!(4-3)!3!⋅(3x)4-3⋅(2)3+4!(4-4)!4!⋅(3x)4-4⋅(2)4

Simplify the exponents for each term of the expansion.

1⋅(3x)4⋅(2)0+4

Hope this helps!

8 0
3 years ago
Read 2 more answers
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
3 years ago
Please help its urgent ​
hram777 [196]

Answer:

<h2>Function is y = x.</h2><h2>Domain: -3 \leq x \leq 2.</h2><h2>Range: -5 \leq y \leq 4.</h2>

Step-by-step explanation:

In the given image, the line passes through (-1, -1) and (1, 1).

Let the equation of the line is y = mx + c, where m is the tangent of the line and c is a constant.

Putting the co-ordinates of the points in the equation, we get -1 = -m + c and 1 = m + c

From the two equations we get, c = 0 and m = 1.

Hence, the function is y = x.

Domain is -3 \leq x \leq 2.

Range is -5 \leq y \leq 4

5 0
3 years ago
the odds of rolling a certain number on a single die is 1 chance in 6 rolls. in course of a game, someone rolled 3 fives. accord
Zina [86]

Answer:

18

Step-by-step explanation:

The expected value is the probability times the frequency.

3 = 1/6 × n

n = 18

Note: the use of the word "odds" is very misleading here.  Odds are the ratio of number of successes to number of failures:

S / F

Probability is the ratio of number of successes to number of all outcomes:

S / (S + F)

So the probability of rolling a 5 is 1/6.  The odds of rolling a 5 is 1/5.

Furthermore, the word "must" is also incorrect.  The player didn't <em>have</em> to roll 18 times.  They could have rolled three times and gotten a 5 each time.  Or they could have rolled 100 times.  18 is simply the most <em>likely </em>number of rolls needed to get three 5's.

6 0
3 years ago
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