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2 years ago

9 + 6 + 5+ 15 Is that

Mathematics

1 answer:

Liula [17]2 years ago

4 0

9+6= 15
15+5=20
20+15=35
35 is the answer.

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What is the slope of the line that passes through the points (6,-5) and (6,-8

sammy [17]

The slope would be undefined.

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3 years ago

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What is the point-slope form of a line with slope 4/5 that contains the point

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Step-by-step explanation:

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3 years ago

Find the values of the ratios

OleMash [197]

Answer:

perimeter: 5/8
area: 25/64

Step-by-step explanation:

You want the ratios (red to blue), of perimeter and area, given that corresponding sides have the ratio red to blue = 5 to 8.

<h3>Perimeter ratio</h3>

The ratio of perimeters is the ratio of corresponding side lengths:

red to blue = 5 / 8

<h3>Area ratio</h3>

The ratio of areas is the square of the ratio of corresponding side lengths:

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<em>Additional comment</em>

Ratios are customarily expressed in any of three equivalent forms:

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1 year ago

Suppose you flip a fair coin N times. Let random variable h be the number of heads that occur. Use the normal approximation to e

Mariana [72]

Answer:

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

Step-by-step explanation:

Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2

The density function of that random variable is given by de following formula

$f_X(k) = \frac{1}{\sqrt{2\pi} * \sigma} e^{\frac{-(k-\mu)^2}{2\sigma^2} } = \frac{2}{\sqrt{2\pi N}} e^{\frac{-2(k-N/2)^2}{N} }$

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

4 0

3 years ago

6n+9=3(6n-2)+2-12n what is the solution set?

Grace [21]

Answer:

No solution

Step-by-step explanation:

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3 years ago

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