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2 years ago

How many pounds of raisins were in her supply when she started?

Mathematics

1 answer:

sp2606 [1]2 years ago

8 0

Answer:

i think it's 15 because if you use 5 and you have to do it by 3 it should be 15

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I have 12 coins x of them are R5 coins and the rest are R1 coins. An expression in the in terms of x for the number of R1 coins

Marrrta [24]

Answer:

ans= 12-x=r1 coin...

Step-by-step explanation:

hope u can do..

7 0

3 years ago

HELP ME PLZ ITS DUE SOON THX

Ad libitum [116K]

Answer:

1.1000

2.3/4

3.f(x)=1000(1/4)^X

Step-by-step explanation:

6 0

3 years ago

On a coordinate plane, a straight line and a parallelogram are shown. The straight line has a negative slope and has a formula o

monitta

Answer:

(1,3)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The blue segment below is a diameter of O. What is the length of the radius of the circle?

svlad2 [7]

Diameter= 2 times the radius

2r=d
2r=10.2
R= 10.2/2
R=5.1

Therefore, the radius is 5.1 units which makes the answer choice C correct.

Hopefully, this helps!

5 0

3 years ago

Read 2 more answers

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago