All categories

3 years ago

List all sets that apply for - 1/2 need help asap

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

1 and 2

2 and 4

3 and 6

4 and 8

5 and 10

6 and 12

7 and 14

8 and 16

9 and 18

10 and 20

here are some examples, there is so much. But I hope this helped you out!

You might be interested in

Which point is located at (-3,6) <br><br> A) A<br><br> B) B<br><br> C) C<br><br> D) D

Andrej [43]

Answer is A

Step-by-step explanation:

Go over to the left 3 times then up 6

3 0

2 years ago

Complementary angles always sum to _____.

dmitriy555 [2]

The answer is: 90° .
______________________________________________________

5 0

3 years ago

Read 2 more answers

A high school football team won 80% of the games they played. If they played 35 games, how many games did they win?

crimeas [40]

Step-by-step explanation:

$formuale \\ \%wom = total \: win \: \times 100\% \div total \: matches \: played$

let x be total much won

$80\% = x \times 100\% \div 35 \\ x= 35 \times 80 \div 100 \\ x = 7 \times 4 \\ x = 28$

so they team had won 28 matches.

I hope the team has best players : )

8 0

3 years ago

A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c

vivado [14]

Answer:

Cost to rent one tank=226.08 Dollars

Step-by-step explanation:

Radius of the cylindrical tank=3 feet

Height of the tank= 2 feet

Cost to rent one tank= Volume of one tank * cost to rent one cubic feet of volume

Volume of the cylindrical tank:

= $\pi r^2$

As, $\pi =\frac{22}{7}=3.14$

Putting the values in the formula:

Volume of the tank:

$=3.14*(3*3)*2\\\\=3.14*9*2\\\\=3.14*18\\\\=56.52feet^3$

Cost to rent one cubic feet= 4 Dollars

Cost to rent 56.52 Cubic feet of one tank;

= 4*56.52

=226.08 Dollars

5 0

3 years ago

Solve the quadratic equation 6x2 + 1 = 5x. Show your work.

Artyom0805 [142]

Answer:

<h2>Factors = (3x - 1) (2x - 1)</h2><h2>values :- x = 1/3 , 1/2</h2>

Step-by-step explanation:

= > 6x^2 + 1 = 5x

• Bring it in the standard form,

= > 6x^2 - 5x + 1 = 0

= > 6x^2 - (3 + 2)x + 1 = 0

= > 6x^2 - 3x - 2x + 1 = 0

• Take out common

= > 3x (2x - 1) - 1 (2x - 1) = 0

= > (3x - 1) (2x - 1) = 0...factors

= > x = 1/3 and 1/2... values of x

<h2>Hope it helps you!! </h2>

7 0

2 years ago