Question

A force of 30 n stretches a very light ideal spring 0. 73 m from equilibrium. What is the force constant (spring constant) of the spring?.

Answer 1

According to Hooke's law, a 30-N force stretches a spring by 0.73 m if the spring constant k is such that

30 N = k (0.73 m)

k = (30 N) / (0.73 m)

k ≈ 4.1 N/m