THE first option is correct
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
Step-by-step explanation:
X^2-6x+5=x^2-5x-x+5=x(x-5)-(x-5)=(x-5)(x-1)
Then we have (x-5)(x-1)=0 if x=5 or x=1.
Intersections on x are points (1,0) and (5,0), middle is (3,0).
Intersection with y is when put x=0 in equation, so you will get y=0-6*0+5, y=5. The point is (0,5).
From picture symmetry is line x=3.
Answer:
m<ADC = 42°
Step-by-step explanation:
Based on the inscribed angle theorem, the inscribed angle, m<ADC is ½ the measure of minor arc AC.
If minor arc is given as 84°, therefore:
m<ADC = ½(84)
m<ADC = 42°