Answer:
y= 23
Step-by-step explanation:
Solve for (y
)
by simplifying both sides of the equation, then isolating the variable.
7y - 6y - 10 = 13
Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Answer:
5750
710.7
Step-by-step explanation:
Simple interest = principal. * rate * time
Principal (p) = sum of money
1380 = p * 0.12 * 2
1380 = 0.24p
p = 1380 / 0.24
p = 5750 rupees.
The compound interest :
A = P(1 + r/n)^nt
A = final amount
n = number of compounding times per period
t = period
A = 5750(1 + 0.12/2)^2*1
A = 5750(1 + 0.06)^2
A = 5750(1.06)^2
A = 5750 * 1.1236
A = 6460.7
Hence, compound interest is :
Final amount - principal
6460.7 - 5750
= 710.7 rupees
I'm assuming you mean (a-b)^2 : (a+b)^2
a^2 + b^2 cancel out leaving
-2ab versus +2ab
Therefore (a+b)^2 is +4ab greater.
Answer:
the second one
Step-by-step explanation:
