2 years ago

Use the key below to report the phenotypes from the provided genotypes.

Biology

1 answer:

Charra [1.4K]2 years ago

7 0

Answer:

Use the key below to report the phenotypes from the provided genotypes.

T= tall B= black eyes L= long hair

t= short b= red eyes l= short hair

1. If the genotype is LlBb

B. Long hair and black eyes

2. If the genotype is TtLL

A. Tall and long hair

3. If the genotype is bbLl

C. Red eyes and long hair

4. If the genotype is ttbb

C. Short and red eyes

5. If the genotype is TTLL

B. Tall and long hair

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2 years ago

Phenylketonuria, PKU, is a single-gene recessive human

astraxan [27]

Answer:

1/2

Explanation:

Let's assume that the allele "p" is responsible for PKU in the homozygous state. According to the given information, both the parents are unaffected by the disorder but have an affected child. This means that both the parents carry at least one copy of the recessive allele responsible for the disease. Therefore, the genotype of each of the parents is Pp. A cross between Pp and Pp would produce progeny in following ratio=

Pp x Pp = 1/4 PP: 1/2/ Pp: 1/4 pp

Therefore, the probability that their next child will carry just one recessive allele is 1/2.