Answer:
x = 3 ±sqrt(6)
Step-by-step explanation:
6(x-3)^2-26 = 10
Add 26 to each side
6(x-3)^2-26+26 = 10+26
6(x-3)^2 = 36
Divide by 6
6/6(x-3)^2 = 36/6
(x-3)^2 = 6
Take the square root of each side
sqrt((x-3)^2) = ±sqrt(6)
x-3 = ±sqrt(6)
Add 3 to each side
x-3+3 =3 ±sqrt(6)
x = 3 ±sqrt(6)
<span> Yes, there is a "relationship" regarding the </span>tangent<span> of the two acute angles (A and B) in a right triangle.</span>
Answer:
The second one is (3 x 3 x 3 x 3) x (3 x 3)
Step-by-step explanation: