Question

Q4.

Answer 1

Probabilities are used to determine the chances of an event

• The probability of choosing a black counter is 0.6
• The probability that both counters are white is 0.16

(a) Probability of selecting two blacks

The probability is given as:

$P(Black\ n\ Black)=0.36$

Apply probability formula

$P(Black) \times P(Black)=0.36$

Express as squares

$P(Black)^2=0.36$

Take the square root of both sides

$P(Black)=0.6$

Hence, the probability of choosing a black counter is 0.6

(b) Probability of selecting two white counters

In (a), we have:

$P(Black)=0.6$

Using the complement rule, we have:

$P(White) = 1 - P(Black)$

So, we have:

$P(White) = 1 -0.6$

Evaluate

$P(White) = 0.4$

The probability that both counters are white is then calculated as:

$P(White\ and\ White) = P(White) \times P(White)$

So, we have:

$P(White\ and\ White) =0.4 \times 0.4$

$P(White\ and\ White) =0.16$

Hence, the probability that both counters are white is 0.16

Read more about probabilities at:

brainly.com/question/15858152