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cluponka [151]
3 years ago
9

The second side of a triangular deck is 4 feet longer than the shortest​ side, and the third side is 4 feet shorter than twice t

he length of the shortest side. If the perimeter of the deck is 52 ​feet, what are the lengths of the three​ sides?
Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

13 ft, 17 ft, 22 ft

Step-by-step explanation:

let x be the shortest side, then second side is x + 4 and the third side is

2x - 4

sum the 3 sides and equate to 52

x + x + 4 + 2x - 4 = 52 , simplify

4x = 52 ( divide both sides by 4 )

x = 13

x + 4 = 13 + 4 = 17

2x - 4 = 2(13) - 4 = 26 - 4 = 22

lengths of 3 sides are 13 ft, 17 ft and 22 ft

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3 years ago
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WILL GIVE BRAINLIEST IF BOTH ARE CORRECT
strojnjashka [21]

Answer:

Q1) D

Q2) C

Step-by-step explanation:

Q1)

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y = kx

Let x=-1,y=2

2 = k(-1)

k = -2

Q2)

directly (y=kx)

Let x=2,y=4

4 = k(2)

k = 2

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inverse (y = k/x)

Let x=2,y = 4

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4 0
3 years ago
Which value of x solves the equation cos x° = sin (20° + x°), where 0 < x < 90? A. 30° B. 35° C. 40° D. 45° E. 55°
daser333 [38]

Answer:

Option B (35°).

Step-by-step explanation:

To solve this question, the trigonometric identity sin x = cos (90-x) is required. It can also be written as cos x = sin (90-x). It can be seen that this identity holds when the two angles are complementary i.e. they sum up to 90 degrees. Therefore, the answer can be determined by substituting all the options one by one in the identity cos x = sin (20+x). If x=30 degrees, then x+20=50 degrees. 30 and 50 are not complementary. If x=35 degrees, then x+20=55 degrees. 35 and 55 are complementary since their sum is 90 degrees. Therefore, B is the correct choice!!!

4 0
3 years ago
Dwight planted some beet plants in his garden. The plants produced 12 beets. He gave 2/3 of the beets to his friend Michael. How
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Answer:8

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6 0
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In the formula ​A(t)equals=Upper A0A0 Superscript ktkt​, A is the amount of radioactive material remaining from an initial amoun
Ivan

Answer:

693 Years

Step-by-step explanation:

Given an initial amount A_o and k (a negative constant) determined by the nature of the material, the amount of radioactive material remaining at a given time​ t, is determined using he formula:

A(t)= A_oe^{kt}

If a certain radioactive isotope decays at a rate of 0.1​% annually.

\frac{1}{2} A_o= A_oe^{-0.001t}\\e^{-0.001t}=\frac{1}{2}\\$Take the natural logarithm of both sides\\-0.001t=ln(0.5)\\t=ln(0.5) \div -0.001\\t=693.15\approx 693 \:years

The half-life of the isotope is 693 years.

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3 years ago
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