First, we put a point at the vertex. Then, we extend a line upwards of slope 1/2 to the right of the vertex. Then extend a line upwards of slope -1/2 to the left of the vertex. This will give the graph of the equation.
Answer:
TT→T
Step-by-step explanation:
If p is false, then ~p is true.
If q is false, then ~q is true.
Now note that
- If a and b are both true, then a→b is true.
- If a is true, b is false, then a→b is false.
- If a is false, b is true, then a→b is true.
- If a and b are both false, then a→b is true.
In your case, both~p and ~q are true, then ~p→~q is true too (or TT→T)
For any arbitrary 2x2 matrices

and

, only one choice of

exists to satisfy

, which is the identity matrix.
There is no other matrix that would work unless we place some more restrictions on

. One such restriction would be to ensure that

is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking

we'd get equality.
If we write y=f(x)=(x-h)²+k, then y-k=(x-h)². This is vertex form where the vertex is (h,k)=(3,3) so h and k are both 3. We can see this if we put x=3 in the shifted function. This is a minimum point for the function because for every other x f(x) is greater then 3. The minimum point is the vertex.