Question

What is the additive inverse of the complex number 9 â€"" 4i? â€""9 â€"" 4i â€""9 4i 9 â€"" 4i 9 4i.

Answer 1

Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.. The additive inverse of the given complex number is

$-9+4i$

Addictive Inverse

Addictive Inverse-Additive inverse is the number you add to a given number to make the sum zero. The addition of both the number must be zero to make both numbers additive inverse.

Let an example, if we take the number 10 and add -10 to it. Thus -10 is the additive inverse of the number 10.

Here, the given number is a complex number. A complex number is a number of the form a + bi, where a and b are real numbers. The given function is,

$9-4i$

The additive inverse of the above number is,$-9+4i$

Add both and check by equating with zero,

$9-4i+(-9i+4)=0$

$9-4i+-9i+4=0$

$0=0$

Hence, the additive inverse of the given complex number is $-9+4i$.

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Answer 2

Answer:

The additive inverse of the complex number 9 - 4i is -9 + 4i.

Step-by-step explanation:

I hope this helps!

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