Answer:
Given statement is TRUE.
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.
Hence given statement is TRUE.
I: 2x+y=5
II:3x+2y=4
start by eliminating y
-2*I: -4x-2y=-10
II: 3x+2y=4
add both equations together
-2*I+II: -4x-2y+3x+2y=-10+4
-1x=-6
x=6
insert x=6 into I:
2*6+y=5
y=5-12
y=-7
so the solution is x=6, y=-7
The answer is $8.75. You have to find what one costs which is 1.25 so if you have 7. 1.25 times 7 is $8.75
