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aleksandr82 [10.1K]

3 years ago

7

Can someone please help, ty!! (Will mark brainliest)

2 answers:

kolezko [41]3 years ago

8 0

$\large\underline{\bf\red{Solution:-}}$

Given two points are :-

( -1 , 3)
( 0 , -5)

So , we know Two point form into equⁿ using a formula , which is

$\boxed{\purple{\bf{\dag y - y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}}}$

So, on substituting respective values ,

=> y - 3 = (-5-3)/0-(-1) × ( x - 3)

=> y - 3 = -8/1 ( x - 3)

=> y - 3 = -8x +24

=> 8x + y -27 = 0

Ivanshal [37]3 years ago

5 0

Answer:

i believe it may be light blue

Step-by-step explanation:

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Which statement is true of the function f(x) = -3 squared root x

grigory [225]

Using translation concepts, it is found that the function $f(x) = -3\sqrt{x}$ is the function $g(x) = \sqrt{x}$ reflected over the x-axis and vertically stretched by a factor of 3.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, from $g(x) = \sqrt{3}$ to $f(x) = -3\sqrt{x}$ , g(x) was multiplied by -3, that is, it was reflected over the x-axis(due to the multiplication by the negative number) and vertically stretched by a factor of 3.

More can be learned about translation concepts at brainly.com/question/27948675

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1 year ago

On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches

Gala2k [10]

Answer:

$g(x)=6(3)^x$

Step-by-step explanation:

We are given that

$f(x)=6(\frac{1}{3})^x$

Function f decreases from quadrant 2 to quadrant 1 and approaches y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

$(x,y)\rightarrow (-x,y)$

Using the rule then we get

$g(x)=6(\frac{1}{3})^{-x}=6(3)^x$

By using

$x^{-a}=\frac{1}{x^a}$

Substitute x=-1

$g(-1)=6\times (\frac{1}{3})=2$

Substitute x=0

$g(0)=6$

Therefore, $g(x)=6(3)^x$ is true.

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attashe74 [19]

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2 years ago

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abruzzese [7]

Answer:

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Step-by-step explanation:

6x - 4 = 8

Add 4 to both sides.

6x = 12

Divide both sides by 6.

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1 year ago

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