Answer:
A) hypertonic, out of the cell.
Explanation:
When cells are exposed to high levels of salt (sodium chloride) they lose water by osmosis and shrink. The cytoplasm condenses and the movement of cellular components, such as the cytoskeleton and organelles, stops. Cells adapt to high salt by quickly importing salt in order to attract water and regain volume, at the expense of increased salt concentration. Unlike cell volume, the movements of cellular components are slow to recover and, depending on the dose of salt, may not recover fully.
Answer:
1. The parents genotypes could have been BO and AO
2. wire-hair
Explanation:
There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:
Blood type possible genotypes
Type A AA, AO
Type B BB, BO
Type AB AB
Type O OO
Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO for them to be able to produce a child with OO. a cross between these two could give rise to OO.
Question 2
Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).
thus, in a cross between homozygous wire haired and smooth haired, we will have:
homozygous wire haired homozygous smooth haired
P gen SS x ss
F1 gen. Ss
phenotype: wire haired
Leave grass clippings on law .
Ÿöu have to add 8 10 times the. You would get 80
