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olya-2409 [2.1K]
3 years ago
13

Jason bought 7 new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There are n

ow only 39 cards left. How many cards did Jason start with ?
Mathematics
1 answer:
Ainat [17]3 years ago
7 0
39 x 2 = 78
Or
38 x 2 + 7 = 85
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Ahat [919]
The triangle is isosceles with  vertex angle =  116 
So m < E  = (180 - 116) / 2 = 32 degrees
8 0
3 years ago
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Solve 3x - x + 2 = 12
Anna11 [10]
Remember you can do anything to an equation as long as you do it to both sides (except divide by 0)

add like terms
3x-x=3x-1x=2x

so
3x-x+2=12
2x+2=12
subtract 2 from both sides
2x=10
divide both sides by 2
x=5
7 0
4 years ago
How do i solve this inequality? -2|3m|+3&lt;-51
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Answer:

m >9  or      m < -9

Step-by-step explanation:

-2|3m|+3<-51

Subtract 3 from each side

-2|3m|+3-3<-51-3

-2|3m|<-54

Divide each side by -2, remembering to flip the inequality

-2|3m|/ -2>-54/-2

|3m|> 27

To get rid of the absolute values, we separate into two inequalities, one as written and one negative, remembering to flip the inequality

3m >27  or     3m <-27

Divide by 3 on each side

3m/3 >27/3  or     3m/3 <-27/3

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4 0
3 years ago
Work out the size of angle x
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70

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angles in a triangle= 180

79+35=110

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8 0
3 years ago
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

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* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
3 years ago
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