Question

Find the Product of (s^2+5s)(s^3+4s^2).

Answer 1

The result of the product $(s^2+5s)(s^3+4s^2)$ is $s^5+9s^4+20s^3$

The product is given as:

$(s^2+5s)(s^3+4s^2)$

Rewrite as:

$(s^2+5s)(s^3+4s^2) = (s^2+5s) \times (s^3+4s^2)$

Expand the expression on the right-hand side

$(s^2+5s)(s^3+4s^2) = s^2\times (s^3+4s^2)+5s \times (s^3+4s^2)$

Distribute the expressions

$(s^2+5s)(s^3+4s^2) = s^5+4s^4+5s^4+20s^3$

Evaluate like terms

$(s^2+5s)(s^3+4s^2) = s^5+9s^4+20s^3$

Hence, the result of the product $(s^2+5s)(s^3+4s^2)$ is $s^5+9s^4+20s^3$

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