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Slav-nsk [51]
3 years ago
8

A publishing company has just published a new college textbook. Before the company decides the price at which to sell this textb

ook, it wants to know the average price of such textbooks in the market. The research department at the company took a sample of 25 comparable textbooks and collected information on their prices. This information produced a mean of $145 for this sample. It is known that the standard deviation of all such textbooks is $35 and the population of such prices is normal.
a. What is the point estimate of the mean price of all such college textbooks?

b. Construct a 90% confidence interval for the mean price of all such college textbooks.
Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

Answer:b

Step-by-step explanation:

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olasank [31]
1.7x 10 =17


Hope this helps
3 0
3 years ago
Two similar pyramids have base areas of 12.2 cm2 and 16 cm2. The surface area of the larger pyramid is 56 cm2. What is the surfa
docker41 [41]

Given =

Two similar pyramid have base area of 12.2 cm² and 16 cm².

surface area of the larger pyramid = 56 cm²

find out the surface area of the smaller pyramid

To proof =

Let us assume that the surface  area of the smaller pyramid be x.

as surface area of the larger pyramid is 56 cm²

Two similar pyramid have base area of 12.2 cm² and 16 cm².

by using ratio and proportion

we have

ratio of the base area of the pyramids : ratio of the surface area  of the pyramids

\frac{12.2}{16} : \frac{x}{56}

x = 12.2 ×56×\frac{1}{16}

by solvingthe above terms

we get

x =42.7cm²

Hence the surface area of the smaller pyramid be 42.7cm²

Hence proved










3 0
3 years ago
Read 2 more answers
If you’re good at geometry solve these 2 please
gizmo_the_mogwai [7]

Answer:

13.

Let us say

first angle be = 4x -10

second angle = x

now add them to 90 as complementary angles add up to 90

4x - 10 + x = 90

5x - 10 = 90

5x = 90+10

5x = 100

x = 100/5

x = 20

the first angle = 4x -10

                       = 4(20) -10

                       = 80 -10

                       = 70

the second angle = x

                             = 20

the angles are 70 and 20

8 0
2 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

18/[(3 - 2(18))] + 4(18 - 8)

You finish.

3 0
3 years ago
Help Q-Q 7/10c =4 1/5
shepuryov [24]

\huge\mathfrak\green{answer}

= q -   \frac{q7}{10} c =  \frac{41}{5}

\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

=  -  \frac{cq7}{10}  =  \frac{41}{5}  - q

\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

=  - cq7 = 82 - 10q

\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

\huge\mathfrak\green{thank \: you}

5 0
3 years ago
Read 2 more answers
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