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2 years ago

PLEASE HELP WILL GIVE BRAINLIEST AND 5.0 RATING

Mathematics

2 answers:

sattari [20]2 years ago

8 0

Answer:

5.4

Step-by-step explanation:

Katarina [22]2 years ago

4 0

Answer:

5.4

Step-by-step explanation:

I just subtracted 8.9 by 3.5 and got 5.4, its probably wrong but try since you never know

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Eamon wants to buy a new baseball glove that costs $50. he has $14 and earns $6 per hour cleaning yards. How many hours must he

konstantin123 [22]

Answer:

The answer is that he would have to work 6 hours to have enough money to buy the glove.

Step-by-step explanation:

1: Find the amount he needs to earn by subtracting $14 from $50: 50 - 14 = 36. So he needs to earn $36.00.

2: Since you have to find the amount of hours, you can divide $6 from $36 to get the amount of hours he needs to work: 36 / 6 = 6. Eamon only gets $6.00 per hour so he would have to work 6 hours to get the $36.00.

3 0

3 years ago

Read 2 more answers

The points (-7,-8) and (8,-8) fall on a particular line. What is its equation in slope-intercept form?

stepan [7]

Y=-8 because there is no slope

7 0

3 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. Calculate the mean

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. Calculate the standard deviation

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

3 years ago

Which of these describes the equation –18x + 9y = –416?

Minchanka [31]

Answer:

We conclude the equation is linear because it can be rewritten in the form $y = mx + b$ .

Hence, option D is correct.

Step-by-step explanation:

The slope-intercept form of the line or linear equation

$y = mx+b$

where

$m$ is the slope

$b$ is the y-intercept

Important Tip:

The graph of a linear equation is always a straight line.

Convert the given equation in the slope-intercept form

$18x + 9y = -416$

subtract 18x from both sides

$18x+9y-18x = - 18x-416$

simplify

$9y = -18x - 416$

divide both sides by 9

$y=-2x-\frac{416}{9}$

Now, comparing the equation $y=-2x-\frac{416}{9}$ with a slop-intercept form of linear equation

The slope m = -2

The y-intercept b = -416/9

Therefore, we conclude the equation is linear because it can be rewritten in the form $y = mx + b$ .

From the attached graph, is also clear that the graph of the equation $y=-2x-\frac{416}{9}$ is a straight line.

Hence, option D is correct.

3 0

3 years ago

Read 2 more answers

Helppp me plsssssssss

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago