(4x^2 -25) /( 2x+5)
Factorise the numerator
((2x)^2 - (5)^2 ) / ( 2x+5)
Applying the Difference of squares
= ((2x +5)(2x -5))/ (2x+5)
(2x+5) cancels in both numerator and denominator
That implies ,
= (2x-5) , with restriction 2x+5 not equals to 0
or x not equals to -5/2
So the first one is the correct answer
(2x+5) , restriction , x not equals to -5/2