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Komok [63]
2 years ago
9

You have been assigned to determine whether more people prefer Coke or Pepsi. Assume that roughly half the population prefers Co

ke and half prefers Pepsi. How large a sample do you need to take to ensure that you can estimate, with 95% confidence, the proportion of people preferring Coke within 3% of the actual value?
Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

You have to add.

Step-by-step explanation:

I'm trash at math.

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Please answer the whole page .
baherus [9]
1. Brandi was driving 60mph down the highway. Ratio is 60/1. 60mi per 1 hr

2. Brandi bought 5 apples at the store and 6 oranges. The ratio of apples to oranges is 5:6 or 5 to 6.

3. Brandi has 3 sisters and 1 brother. Ratio of sisters to brothers is 3:1 or 3 to 1.

4. Brandi has 20 shirts and 10 pants in her closet. The ratio of shirts to pants is 20:10 or 20 to 10.

5. Brandi has 12 boys in her class and 13 girls. The ratio of boys to girls is 12:13 or 12 to 13

Hope this helps:)
7 0
3 years ago
Evaluate 5c+cd when c=1/5 and d=15
Ad libitum [116K]
5c = 1
cd = 3
5c + cd = 4
8 0
3 years ago
Read 2 more answers
If the lines x+y=5 and 2x +2y+6=0 are parallel, find the distance between them
kobusy [5.1K]
Pretty sure the distance is 8 units
5 0
3 years ago
**20 POINTS + BRAINLIEST** Please help me with the math question!
aliina [53]

Answer:

1/6.2=15/x

Step-by-step explanation:

15:x=1:6.2

6 0
3 years ago
Read 2 more answers
7. The manager of the soda shop decides that because you are a good customer, you may use a flavor as many times as you’d like.
Black_prince [1.1K]

The different possible mixtures can you make is 1716 .

<u>Step-by-step explanation:</u>

Given that,

  • The total number of flavors available in the shop = 13 flavors
  • The number of flavors you need to choose = 6 flavors

Here, we have to use  the formula for combination,

nCr = n! / r! × (n-r) !

where,

  • n is the total number of flavors
  • r is the number of flavors you need to choose

⇒ 13C6 = 13 ! / 6! × (13-6)!

⇒ 13! / (6! × 7! )

⇒ 13 × 12 × 11 × 10 × 9 × 8 × 7! / (6! × 7! )

⇒ 13 × 12 × 11 × 10 × 9 × 8 / 6!

⇒ 13 × 12 × 11 × 10 × 9 × 8 / 6 × 5 × 4 × 3 × 2 × 1

⇒ 1716

Therefore, you can 1716 different possible mixtures.

3 0
3 years ago
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