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grin007 [14]
4 years ago
9

f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.

Mathematics
2 answers:
Feliz [49]4 years ago
7 0
The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i  is one imaginary root and the other is  2 + i
faltersainse [42]4 years ago
4 0

Answer:

The function has

2 real roots and

2 imaginary roots.

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