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3 years ago

5

X= [ ? ]° 104° 1170 1249 100°

2 answers:

NikAS [45]3 years ago

8 0

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkk

Studentka2010 [4]3 years ago

5 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Sum of angles of a pentagon is ~ 540°

Therefore,

$\sf104 + 117 + 100 + 124 + x = 540$

$\sf445 + x = 540$

$\sf x = 540 - 445$

$\sf x = 95 \degree$

Value of x = 95°

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Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15

ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

$a_{n+1} = ra_{n}$

In which r is the common ratio.

This can be expanded for the nth term in the following way:

$a_{n} = a_{1}r^{n-1}$

In which $a_{1}$ is the first term.

Or even:

$a_{n} = a_{m}r^{n-m}$

The sum of the first n terms of a geometric sequence is given by:

$S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}$

Finding the common ratio:

$a_{3} = 3.645, a_{8} = 15$

$a_{n} = a_{m}r^{n-m}$

$a_{8} = a_{3}r^{8-3}$

$a_{3}r^{5} = a_{8}$

$3.645r^{5} = 15$

$r^{5} = \frac{15}{3.645}$

$r = \sqrt[5]{\frac{15}{3.645}}$

$r = 1.327$

Finding the first term:

$a_{3} = a_{1}r^{2}$

$a_{1} = \frac{a_{3}}{r^{2}}$

$a_{1} = \frac{3.645}{(1.327)^{2}}$

$a_{1} = 2.07$

Sum of the first nine terms:

$S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44$

The sum of the first nine terms of the sequence is 74.44.

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<span>If f(x)= 5x+40 what is f(x) when x =-5
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