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2 years ago

Using the points on the diagram below, name another segment that would definitely be congruent to BA.

Mathematics

1 answer:

disa [49]2 years ago

7 0

BC it’s the same which
Means congruent it’s just on the other side

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Wade was asked to solve this inequality:

frozen [14]

Answer:

The correct option is Option A: Yes, that is the correct step

Step-by-step explanation:

Wane was asked to solve the inequality $\large \frac{x}{3}\ge11$

He decides that he needs to multiply both sides by 3.

We need to tell if the step is correct?

So, solving the inequality

$\frac{x}{3}\ge11$

We need to multiply both sides by 3, to get value of x i.e.

$\frac{x}{3}*3\ge11*3\\x\geq 33$

So, Wanes step is correct.

The correct option is Option A: Yes, that is the correct step

6 0

3 years ago

Each table shows a proportional relatioship. fill in the missing values and determine k.

kolbaska11 [484]

Answer:

what table ..............there is no table

8 0

3 years ago

brainly The point (−4, 2) is on the terminal side of angle Θ, in standard position. What are the values of sine, cosine, and tan

olganol [36]

The tangent = -2/4 = -1/2
The length of the hypotenuse = sqrt20 = 2 sqrt5
sine = 2 / 2 sqrt5 = 1 / sqrt5
cosine = -4 / 2 sqrt5 = -2/sqrt5

3 0

3 years ago

What is the y intercept of f(x)=(1/2)*

9966 [12]

Answer:

B. (0,0)

Step-by-step explanation:

The y-intercept of the equation f(x) = 1/2x lies on the y-axis.

This means we need to set x = 0 and solve for y

1/2(0) = 0

Therefore, (0,0) is the y-intercept of this equation.

5 0

3 years ago

$6,000 for 6 years at 8½% compounded daily will grow to ?

iren [92.7K]

When an amount $P$ is invested for $t$ years during which it earns an interest of $r$ dollars compounded $m$ times per year, the formula to calculate the amount that investment grows to after $t$ years is,

$A=P(1+\tfrac{r}{m})^{mt}.$

Assuming that a years has 365 days ,the values for each of these variables is given as follows, $m=365$ , $t=6$ $r=8.5\%=0.085 .$ The value of the investment after 6 years is then calculated as shown below,

$A=P(1+\tfrac{r}{m})^{mt}\\A=6000(1+\tfrac{0.085}{365})^{(365\times 6)}\\A=9991.15$

The investment grows to reach $9991.15 in 6 years.

8 0

3 years ago