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Nikolay [14]
3 years ago
5

Find the slope of the line that passes through (7, 1) and (2, 8).

Mathematics
2 answers:
sashaice [31]3 years ago
8 0

Answer:-1.4

Step-by-step explanation: The slope or gradient is given by

Slope=y2-y1÷x2-x1.

From the problem

X1=7

Y1=1

X2=2

Y2=8

Thus we will have

Slope=(8-1)÷(2-7)

=7÷(-5)

=-1.4

kvasek [131]3 years ago
7 0

Answer:

-7/5

Step-by-step explanation:

(1-8)/(7-2)= -7/5

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Question 10(Multiple Choice Worth 1 points)
pshichka [43]

we are given

Line A: y = x − 6

Line B: y = 3x + 4

so, we can solve it

we can set them equal

and then we can solve for x

y=x-6=3x+4

now, we can solve for x

-2x=10

x=-5

now, we can find y

y=-5-6

y=-11

so, we will get intersection points as

(x,y)=(-5,-11)

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4 0
4 years ago
Read 2 more answers
Write the equation in standard form for the circle with center (0, -2) and radius 7.
ExtremeBDS [4]

Answer:

(x)^2+ (y+2)^2 = 49

Step-by-step explanation:

The standard form of a circle is

(x-h)^2+ (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-0)^2+ (y--2)^2 = 7^2

(x)^2+ (y+2)^2 = 49

7 0
3 years ago
What is the equation of this line *
balandron [24]

Answer:

I would have to see the line to answer the question.

8 0
3 years ago
What is the sum of the first 5 terms of geometric series with a1=10 and r=1/5
steposvetlana [31]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=10\\
n=5\\
r=\frac{1}{5}
\end{cases}

\bf S_5=10\left( \cfrac{1-\left( \frac{1}{5} \right)^5}{1-\frac{1}{5}} \right)\implies S_5=10\left( \cfrac{1-\frac{1}{3125}}{\frac{4}{5}} \right)
\\\\\\
S_5=10\left( \cfrac{\frac{3124}{3125}}{\frac{4}{5}} \right)\implies S_5=10\cdot \cfrac{781}{625}\implies S_5=\cfrac{1562}{125}
7 0
3 years ago
Hi, I need help asap thx u
Delvig [45]
The answer would be x^-10

Hope this helps

Have a great day/night

Feel free to ask any questions
8 0
3 years ago
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