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2 years ago

Write your number as a while number.

Mathematics

2 answers:

Tom [10]2 years ago

7 0

Answer: 16

4 * 12 / 3

48/3

Brainliest pweasee if my answer is clear and correct! <3 ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Reil [10]2 years ago

4 0

Ans

=16

Step-by-step explanation:

=4×12/3

= 48/3

=16

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Sean's new baby brother weighs 125.2 ounces. A nurse writes the weight in the chart rounded to the nearest ounce. Which is the w

Naily [24]

The answer would have to be A because if it's ROUNDED to the nearest ounce then 2 is closer to 0 so it would be A

6 0

3 years ago

In Exercise, evaluate each expression.<br> 643/4

Goshia [24]

Answer:

$\\ 64^{\frac{3}{4}} = 16\sqrt{2}$

Step-by-step explanation:

We need here to remember that:

$\\{(x^{a})}^{b} = x^{a * b}$

$\\{x^{a} * x^{b} = x^{a + b}$

Then,

$\\ 64^{\frac{3}{4}} = {(8^{2})}^{(\frac{3}{4})} = {{(2^{3})}^{2}}^\frac{3}{4}$

$\\ 64^{\frac{3}{4}} = {{2^{3}}^2}^\frac{3}{4} = 2^\frac{3*2*3}{4}$

$\\ 64^{\frac{3}{4}} = 2^\frac{2*3*3}{4} = 2^\frac{3*3}{2} = 2^\frac{9}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}}$

Since $\\ \frac{9}{2} = \frac{4}{2} + \frac{4}{2} + \frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}} = {2^{(\frac{4}{2} + \frac{4}{2} + \frac{1}{2})}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{4}{2}} * 2^{\frac{4}{2}} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{2} * 2^{2} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 4 * 4 * \sqrt{2} = 16 \sqrt{2}$

5 0

3 years ago

(17^4)^6 <br><br> urgent please help?

qaws [65]

The answer would be 3.3944867e+29 but seeing how you didn’t give more detailing I’m not sure if it’s specifically the answer you need.

5 0

3 years ago

(geometry) please look at attached image and help me with this question!

julsineya [31]

Answer:

m∠AEC = 139°

Step-by-step explanation:

To make the equations easier to write, let's say all measures are in degrees, and define ...

p = m∠AEB = 11x -12

q = m∠CED = m∠CEB = 4x +1

Then ...

p + 2q = 180

(11x -12) + 2(4x +1) = 180

19x -10 = 180 . . . . . . . . . . . . collect terms

19x = 190 . . . . . . . . add 10

x = 10 . . . . . . . . . . . divide by 19

p = 11x -12 = 110 -12 = 98

q = 40 +1 = 41

The angle of interest is ...

m∠AEC = p +q = 98 +41

m∠AEC = 139 . . . . degrees

8 0

3 years ago

The length of a rectangular garden is 8 feet longer than it’s width. The garden is surrounded by a sidewalk that is 4 feet wide

Westkost [7]

Answer:

The length = 20
The width = 12

Explanation:

Let the Length of the garden be L and the Width W
Therefore the area of the garden = L*W
But we know that L = W + 8
Therefore the area of the garden can be expressed as W*(W + 8)
When the brackets are expanded this equals W^2 + 8W

The area of the recctangle which includes the path and garden will have a length of L + 8 (ie the length of the garden + 4 feet at the top and 4 feet at the bottom)
The width will be W + 8 (width of garden + 4 feet at the left and 4 feet at the right)
Therefore the area will be (W + 8)*(L +8)
Once again we know that L = W + 8
Therefore the area of the path/garden = (W +8)(W +8 +8)
=(W +8)(W +16)
=W^2 +24W + 128

We know that the path alone has an area of 320 square feet. Therefore if we subtract the area of the garden (W^2 + 8W) from the area of the path/garden the area left is the area of the path only

Therefore W^2 + 24W + 128 - (W^2 + 8W) = 320
W^2 + 24W + 128 - W^2 - 8W = 320
Simplify
16W + 128 = 320
Subtract 128 from both sides of the equation
16W = 192
divide both sides of the equation by 16
W = 12
As L = W + 8
L = 12 + 8 = 20

7 0

3 years ago