Using a calculator or otherwise, calculate the exact value of 498.79×14.38. Round your answer to one (1) decimal place.

Cayden wants to buy a television that costs $600, including taxes. To pay for the television, he will use a payment plan that re

kobusy [5.1K]

well, the regular cost of the TV is 600 bucks, that includes taxes already, so is just 600 flat.

the payment plan makes Cayden pay 225 first, leaving 375 for periodic payments for 6 months, each payment of 74.50.

well, 74.5*6 = 447, so Cayden is paying 225 + 447 = 672, so the increase is 72 bucks.

If we take 600 to be the 100%, how much is 72 off of it in percentage?

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 600&100\\ 72&x \end{array}\implies \cfrac{600}{72}=\cfrac{100}{x}\implies \cfrac{25}{3}=\cfrac{100}{x} \\\\\\ 25x=300\implies x=\cfrac{300}{25}\implies x=12$

7 0

2 years ago

Your car insurance comes due annually and generally costs about $1,500. You decide that you would like to set aside a monthly am

Volgvan

Answer:

$125

Step-by-step explanation:

Since there are 12 months in a year, divide the total bill by the total number of months.

1500/12 = $125

5 0

3 years ago

El numero 38 es par o impar<br> El numero 35 es par o impar?

lara [203]

38 es par 35 es par eso es todo?

7 0

3 years ago

Read 2 more answers

The population of bacteria in a petri dish doubles every 12 h. The population of the bacteria is initially 500 organisms. How lo

Alenkasestr [34]

Answer:

The answer is 8.1 h

Good luck!!!!!

Step-by-step explanation:

6 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$